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f′

Derivatives of standard functions (the formulas)

Level 6 · Ages 16–17

Quick recall· Let's wake up what you already know before we start.

Recap: what does the derivative f′(a) represent?

The whole lesson

Read it again any time, including while you work through the exercises.

You already know what the derivative at a point represents: the slope of the tangent line to the curve, that is, how fast the function is changing there. But computing that slope by hand, with a rate of change, is slow. Good news: for the standard functions, the work has been done once and for all, and you just need to know the formulas.

The star of the table is the power rule: the derivative of xⁿ is n·xⁿ⁻¹. The exponent drops down in front as a coefficient, and the exponent goes down by 1. So the derivative of x² is 2x, that of x³ is 3x², that of x⁴ is 4x³. Two extreme cases to remember: the derivative of x is 1, and the derivative of a constant is 0 (a constant function does not change, its slope is zero everywhere).

Two more formulas complete the kit: the derivative of 1/x is -1/x², and the derivative of √x is 1/(2√x). Notice that both are consistent with the power rule, since 1/x = x⁻¹ and √x = x^(1/2).

Finally, two combination rules make the table truly powerful: the derivative of k·f is k·f′ (a multiplicative constant stays as a factor), and the derivative of a sum is the sum of the derivatives. With these, you can differentiate any polynomial term by term, in seconds.

The worked example, step by step

Differentiate f(x) = x³ using the power rule.

  1. (xⁿ)′ = n·xⁿ⁻¹

    I start from the general formula: the exponent drops down as a coefficient, then goes down by 1.

  2. n = 3

    Here the exponent is 3: it drops in front, and the new exponent is 3 - 1 = 2.

  3. f′(x) = 3x²

    I get 3x². Quick check: the derivative of x² is indeed 2x with the same rule, so the mechanics are consistent.

Result: If f(x) = x³, then f′(x) = 3x².

Differentiate f(x) = 5x² + 3x - 7.

  1. (5x²)′ = 5 × 2x = 10x

    I differentiate term by term. The coefficient 5 stays as a factor, and the derivative of x² is 2x.

  2. (3x)′ = 3

    The derivative of x is 1, so the derivative of 3x is 3.

  3. (-7)′ = 0

    The derivative of a constant is zero: the -7 vanishes.

  4. f′(x) = 10x + 3

    I add the three derivatives. Double check: 10x comes from 5x², 3 comes from 3x, and nothing from -7. All good.

Result: f′(x) = 10x + 3