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Probability: random experiments and equally likely outcomes

Level 4 · Ages 13–15

Quick recall· Let's wake up what you already know before we start.

Recap: write the fraction 1/2 as a decimal.

The whole lesson

Read it again any time, including while you work through the exercises.

Tossing a coin, rolling a die, drawing a ball from a bag without looking: in each case, you cannot predict the result with certainty. This is called a random experiment. The possible results are called outcomes: heads or tails for the coin, the numbers 1 to 6 for the die.

Even if we cannot predict the result, we can measure the chance of each outcome with a number: its probability. It is a number between 0 and 1. Probability 0: impossible (rolling a 7 with a standard die). Probability 1: certain (rolling a number between 1 and 6). In between, every shade of "maybe".

When all outcomes have exactly the same chance, we say they are equally likely. A well-balanced die, a fair coin: every outcome has the same probability. In that case, the formula is simple: probability = number of favourable outcomes divided by number of possible outcomes. To roll a 3 with a die: 1 favourable outcome out of 6 possible, so 1/6.

Watch out for the famous trap: two outcomes does not mean a one-in-two chance! In a bag with 3 red balls and 2 blue balls, there are indeed two colours, but the probability of drawing a red one is 3/5, not 1/2, because there are more red balls. Equal likelihood has to be checked, not guessed.

A probability can be written as a fraction (1/2) or as a decimal (0.5): it is the same number. In this lesson you will learn to count outcomes, spot equal likelihood and compute your first probabilities.

The worked example, step by step

We roll a fair 6-sided die. What is the probability of getting a 3?

  1. issues possibles : 1, 2, 3, 4, 5, 6

    I list all the possible outcomes: there are 6, and the die is fair, so they all have the same chance.

  2. issues favorables : 3 -> 1 issue

    Only one outcome works for me: getting a 3.

  3. P(3) = 1/6

    I apply the formula: favourable over possible, that is 1 out of 6.

Result: P(getting a 3) = 1/6.

With the same die, what is the probability of getting an even number?

  1. favorables : 2, 4, 6 -> 3 issues

    I count the favourable outcomes: three even numbers on the die.

  2. P(pair) = 3/6 = 1/2 = 0,5

    3 out of 6 simplifies to 1/2, that is 0.5 as a decimal: a one-in-two chance.

Result: P(even) = 1/2 = 0.5.